2x^2-7x+12=1

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Solution for 2x^2-7x+12=1 equation:


Simplifying
2x2 + -7x + 12 = 1

Reorder the terms:
12 + -7x + 2x2 = 1

Solving
12 + -7x + 2x2 = 1

Solving for variable 'x'.

Reorder the terms:
12 + -1 + -7x + 2x2 = 1 + -1

Combine like terms: 12 + -1 = 11
11 + -7x + 2x2 = 1 + -1

Combine like terms: 1 + -1 = 0
11 + -7x + 2x2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
5.5 + -3.5x + x2 = 0

Move the constant term to the right:

Add '-5.5' to each side of the equation.
5.5 + -3.5x + -5.5 + x2 = 0 + -5.5

Reorder the terms:
5.5 + -5.5 + -3.5x + x2 = 0 + -5.5

Combine like terms: 5.5 + -5.5 = 0.0
0.0 + -3.5x + x2 = 0 + -5.5
-3.5x + x2 = 0 + -5.5

Combine like terms: 0 + -5.5 = -5.5
-3.5x + x2 = -5.5

The x term is -3.5x.  Take half its coefficient (-1.75).
Square it (3.0625) and add it to both sides.

Add '3.0625' to each side of the equation.
-3.5x + 3.0625 + x2 = -5.5 + 3.0625

Reorder the terms:
3.0625 + -3.5x + x2 = -5.5 + 3.0625

Combine like terms: -5.5 + 3.0625 = -2.4375
3.0625 + -3.5x + x2 = -2.4375

Factor a perfect square on the left side:
(x + -1.75)(x + -1.75) = -2.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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